Java Program to Find Reverse Number of a Given Number

In the previous article, we have discussed Java Program to Check Spy Number

In this article we are going to understand what Reverse number is and how we can check whether a number is Reverse or not in Java with examples.

Program to Find Reverse Number of a Given Number

Reverse numbers are numbers formed after reversing the digits

 Example :

19 =>91
46 =>64

In the above examples the reverse of 19 and 46 are 91 and 64 respectively.

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Approach :

We ask the user to enter a number and store it.
We iterate through its digits inside a loop and store them in another variable.
The reverse number inside the variable is printed.

Let’s see different ways to find reverse of a number.

By Using Static Value
By User Input Value
By C Language

Method-1: Java Program to find Reverse Number of a Given Number By Using Static Value

import java.util.Scanner;
public class ReverseNumber
{
    public static void main(String args[])
    {
        //number declared;
        int num = 67;

        int rev=0,remainder,temp=num;
        while(temp>0)
        {
            remainder=temp%10;
            rev = rev*10+remainder;
            temp=temp/10;
        }

        System.out.println("The reverse of "+num+" is "+rev);
    }
}

Output:

The reverse of 67 is 76

Method-2: Java Program to find Reverse Number of a Given Number By User Input Value

import java.util.Scanner;
public class ReverseNumber
{
    public static void main(String args[])
    {
        //Taking the number as input from the user using scanner class
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter a number : ");
        int num = scan.nextInt();

        int rev=0,remainder,temp=num;
        while(temp>0)
        {
            remainder=temp%10;
            rev = rev*10+remainder;
            temp=temp/10;
        }

        System.out.println("The reverse of "+num+" is "+rev);
    }
}

Output:

Enter a number : 45
The reverse of 45 is 54

By C Programming Language:

#include <stdio.h>
int main()
{
    int number, reverse = 0, remainder;
    printf("Enter an integer: ");
    //taking anumber inputfrom user
    scanf("%d", &number);
    
    //Reversing anumber
    while (number != 0) {
        remainder = number % 10;
        reverse = reverse * 10 + remainder;
        number /= 10;
    }
    printf("Reversed number: %d", reverse);
    return 0;
}

Output:

Enter an integer: 78
Reversed number = 87

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