In the previous article, we have seen Java Program to Find Surface Area of Hemisphere

In this article we are going to see how to find the maximum volume of cuboid that can be achieved with given sum of sides using Java programming language.

## Java Program to Find Maximum Volume of Cuboid that can be Achieved with Given Sum of Sides

Before Jumping into the program directly let’s see how we can Find Maximum Volume of Cuboid that can be Achieved with Given Sum of Sides..

**Explanation:**

Let the sum of length, breadth and height be “S”, of a cuboid. The task is to find the maximum volume that can be achieved so that sum of side is S. Volume of a cuboid = length * breadth * height

**Example:**

let S = 8 All possible edge size be: [1, 1, 6], volume = 6 [1, 2, 5], volume = 10 [1, 3, 4], volume = 12 [2, 2, 4], volume = 16 [2, 3, 3], volume = 18 Max volume out of those possible edge sizes = 18

Let’s see different ways to find the maximum volume of cuboid that can be achieved with given sum of sides.

### Method-1: Java Program to Find Maximum Volume of Cuboid that can be Achieved with Given Sum of Sides By Using Static Value

**Approach:**

- Declare an integer variable say ‘
`s`

’ and assign the value to it, which holds the sum of the sides of the cuboid. - Call a method
`maxvolume(int s)`

where find the max volume of the cuboid using the formula`maxvalue = Math.max(maxvalue, i * j * k)`

where`i`

,`j`

,`k`

are the local variable to store the value of length, breadth, height of the cuboid. - Print the result.

**Program:**

import java.io.*; public class Main { static int maxvolume(int s) { int maxvalue = 0; // for length for (int i = 1; i <= s - 2; i++) { // for breadth for (int j = 1; j <= s - 1; j++) { // for height int k = s - i - j; // calculating maximum volume. maxvalue = Math.max(maxvalue, i * j * k); } } return maxvalue; } // Driver function public static void main (String[] args) { int s = 8; System.out.println("The max vol of the cuboid is: " + maxvolume(s)); } }

Output: The max vol of the cuboid is: 18

### Method-2: Java Program to Find Maximum Volume of Cuboid that can be Achieved with Given Sum of Sides By Using User Input Value

**Approach:**

- Declare an integer variable say ‘
`s`

’ and take it’s value as user input, which holds the sum of the sides of the cuboid. - Call a method
`maxvolume(int s)`

where find the max volume of the cuboid using the formula`maxvalue = Math.max(maxvalue, i * j * k)`

where`i`

,`j`

,`k`

are the local variable to store the value of length, breadth, height of the cuboid. - Print the result.

**Program:**

import java.util.*; public class Main { static int maxvolume(int s) { int maxvalue = 0; // for length for (int i = 1; i <= s - 2; i++) { // for breadth for (int j = 1; j <= s - 1; j++) { // for height int k = s - i - j; // calculating maximum volume. maxvalue = Math.max(maxvalue, i * j * k); } } return maxvalue; } // Driver function public static void main (String[] args) { //Scanner class object created Scanner sc = new Scanner(System.in); //taking input of sum value of all the sides of cuboid System.out.println("Enter the sum of sides of the cuboid: "); int s = sc.nextInt(); System.out.println("The max vol of the cuboid is: " + maxvolume(s)); } }

Output: Enter the sum of sides of the cuboid: 18 The max vol of the cuboid is: 216

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