# Java Program to Find Even Numbers in an Array by Using Recursion

Prerequisite: Recursion in Java

In the previous article, we have discussed about Java Program to Find Odd Numbers in an Array by Using Recursion

In this program we are going to see how to find odd numbers in an Array by using Recursion in Java programming language.

## Java Program to Find Even Numbers in an Array by Using Recursion

Lets assume there is an array say A[] which has 5 elements {70, 82, 33, 17, 95}

Even numbers in the array A = 70, 82

Total even numbers in the array A = 2

Now let’s see different ways to find odd numbers in an Array by using Recursion.

### Method-1: Java Program to Find Even Numbers in an Array By Using Static Input and Recursion

Approach:

• Declare and initiate an integer Array ‘A[]‘.
• Call a user defined method countEven() and pass the array ‘A[]’ with first index and last index of the array as parameter.
• Inside the user defined method we will declare and initialize an integer variable say ‘count’ as 0.
• Check the element is even or odd if the element is even then increment count value and call the countEven() method recursively by passing the array ‘A[]’ with next index and last index of the array as parameter.
• Now the value of the user defined method countEven() is stored in an integer variable say ‘m’.
• Print the number of even elements in the array.

Program:

import java.util.*;
import java.io.*;
public class Main
{
public static void main(String[] args)
{
//declare and initialize an array A
int A[] = {70, 82, 33, 17, 95};
//calling the user defined method countEven()
//and store the result value inside an integer variable say ‘m’
int m = countEven(A, 0, A.length - 1);
//print the result
System.out.println("The number of even elements in the array are: " + m);
}

//countEven() method
public static int countEven(int A[], int firstIndex, int lastIndex)
{
int count = 0;
//checking numbers of elements in the array
if(firstIndex <= lastIndex)
{
// if the element is even then the count is incremented
if(A[firstIndex] % 2 == 0)
{
count++;
}
count+=countEven(A, firstIndex + 1, lastIndex);
}
return count;
}
}
Output:

The number of odd elements in the array are: 3

### Method-2: Java Program to Find Odd Numbers in an Array by Using Recursion By Using User Input and Recursion

Approach:

• Create a scanner class.
• Declare an integer variable say ‘n
• Prompt the user to enter the size of the array.
• Declare an integer array say ‘A[]
• Prompt the user to enter the elements inside the array.
• The elements inside the Array A[] are added in sequential index position using a for loop. Where the loop starts from i=0 to i<n and the loop is incremented by 1.
• Call a user defined method countEven() and pass the array ‘A[]’ with first index and last index of the array as parameter.
• Inside the user defined method we will declare and initialize an integer variable say ‘count’ as 0.
• Check the element is even or odd if the element is even then increment count value and call the countEven() method recursively by passing the array ‘A[]’ with next index and last index of the array as parameter.
• Now the value of the user defined method countEven() is stored in an integer variable say ‘m’.
• Print the number of even elements in the array.

Program:

import java.util.*;
import java.io.*;
public class Main
{
public static void main(String[] args)
{
// create a scanner class
Scanner s = new Scanner(System.in);
System.out.println("Enter no. of elements you want in array:");
//declare the size of the array
int n = s.nextInt();
// declare the array and initialize it with user input
int A[] = new int[n];
System.out.println("Enter all the elements:");
//get all the elements sequentially
for(int i = 0; i < n; i++)
A[i] = s.nextInt();
//calling the user defined method CountEven()
//and store the result value inside an integer variable say ‘m’
int m = countEven(A, 0, A.length - 1);
//print the result
System.out.println("The number of even elements in the array are: " + m);
}

//countEven() method
public static int countEven(int A[], int firstIndex, int lastIndex)
{
int count = 0;
//checking numbers of elements in the array
if(firstIndex <= lastIndex)
{
// if the element is even then the count is incremented
if(A[firstIndex] % 2 == 0)
{
count++;
}
count+=countEven(A, firstIndex + 1, lastIndex);
}
return count;
}
}
Output:

Enter no. of elements you want in array:
5
Enter all the elements:
2
3
4
5
6
The number of even elements in the array are: 3



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