In the previous article, we have seen Java Program to Find all the Triplets Where Sum of All the Three Elements are Equal to a Specified Number
In this article we are going to see how to find all the Combination of Four Elements Where Sum of All the Three Elements are Equal to a Specified Number.
Java Program to Find all the Combination of Four Elements Where Sum of All the Four Elements are Equal to a Specified Number
Array is a data structure which stores a fixed size sequential collection of values of single type. Where with every array elements/values memory location is associated. Each array elements have it’s own index where array index starts from 0.
In Array set of variables referenced by a single variable name and it’s array index position. It is also called as a container object which contains elements of similar type.
Declaration of an array:
dataType[] arrayName; (or) //Declaring an array dataType []arrayName; (or) dataType arr[];
Instantiation of an Array:
arrayName = new datatype[size]; //Allocating memory to array
Combining both Statements in One:
dataType[] arrayName = new dataType[size] //Declaring and Instantiating array
Initialization of an Array:
arrayName[index-0]= arrayElement1 //Initializing the array ... arrayName[index-s]= arrayElementS
Combining all Statements in One:
dataType arrayName[ ]={e1,e2,e3}; //declaration, instantiation and initialization
Let’s see different ways to find all the Triplets Where Sum of All the Three Elements are Equal to a Specified Number
Method-1: Java Program to Find all the Combination of Four Elements Where Sum of All the Four Elements are Equal to a Specified Number By Static Initialization of Array Elements
Approach:
- Create four nested for loops and compare each quadruple with the required sum.
- If it’s equal, print the quadruple.
Program:
public class Main { public static void main(String[] args) { int[] arr = { 2, 3, 6, 7, 4, 1, 5, 0 }; int sum = 14; System.out.println("Finding quadruple whose sum are equal to : "+sum); System.out.println("The quadruple are : "); findQuadruples(arr, sum); } static void findQuadruples(int[] arr, int sum) { int count = 1; int n = arr.length; for (int i = 0; i < n - 3; i++) { for (int j = i + 1; j < n - 2; j++) { for (int k = j + 1; k < n - 1; k++) { for (int l = k + 1; l < n; l++) { if (arr[i] + arr[j] + arr[k] + arr[l] == sum) { System.out.print("Quadruple " + count + ": " + arr[i] + " " + arr[j] + " " + arr[k] + " " + arr[l] + "\n"); count++; break; } } } } } } }
Output: Finding quadruple whose sum are equal to : 14 The quadruple are : Quadruple 1: 2 3 4 5 Quadruple 2: 2 6 1 5 Quadruple 3: 2 7 4 1 Quadruple 4: 2 7 5 0 Quadruple 5: 3 6 4 1 Quadruple 6: 3 6 5 0 Quadruple 7: 3 7 4 0 Quadruple 8: 6 7 1 0
Method-2: Java Program to Find all the Combination of Four Elements Where Sum of All the Four Elements are Equal to a Specified Number By Dynamic Initialization of Array Elements
Approach:
- Create scanner class object.
- Ask use length of the array.
- Initialize the array with given size.
- Ask the user for array elements.
- Create four nested for loops and compare each quadruple with the required sum.
- If it’s equal, print the quadruple.
Program:
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); // asking user to enter the number of elements System.out.println("Enter number of elements in the array: "); int n = sc.nextInt(); // initializing the array int[] arr = new int[n]; // asking user to enter the elements System.out.println("Enter elements of the array: "); for (int i = 0; i < n; i++) { arr[i] = sc.nextInt(); } // asking user to enter the required sum System.out.println("Enter the required sum: "); int sum = sc.nextInt(); System.out.println("Finding quadruple whose sum are equal to : "+sum); System.out.println("The quadruple are : "); findQuadruples(arr, sum); } static void findQuadruples(int[] arr, int sum) { int count = 1; int n = arr.length; for (int i = 0; i < n - 3; i++) { for (int j = i + 1; j < n - 2; j++) { for (int k = j + 1; k < n - 1; k++) { for (int l = k + 1; l < n; l++) { if (arr[i] + arr[j] + arr[k] + arr[l] == sum) { System.out.print("Quadruple " + count + ": " + arr[i] + " " + arr[j] + " " + arr[k] + " " + arr[l] + "\n"); count++; break; } } } } } } }
Output: Enter number of elements in the array: 8 Enter elements of the array: 6 3 1 2 4 7 5 4 Enter the required sum: 12 Finding quadruple whose sum are equal to : 12 The quadruple are : Quadruple 1: 6 3 1 2 Quadruple 2: 3 1 4 4 Quadruple 3: 1 2 4 5 Quadruple 4: 1 2 5 4
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