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## Program to Display Factors of a Number

In this article, we will learn multiple ways to display the factors of a number.

A factor is defined as the number which is perfectly divisible by other number. Now, our task is to display all the factors of a number.

We will see different approaches to get achieve it.

- Java program to display factors of positive number using for loop
- Java program to display factors of positive number using user-defined input
- Java program to display factors of negative number using for loop
- Java program to display factors of number using while loop
- Java program to display factors of number using do-while loop
- Java program to display factors of number using recursion

Let’s see different methods on by one.

### Method:-I – Java program to display factors of positive number using for loop

Factors of a positive number can be displayed by taking a for loop. The for loop will iterate from 1 till the number, wherever number is perfectly divisibly by iterative value, print the iterative value. The values obtained are the factors of the number.

**Approach:**

- Declare an int variable say
`num`

and store a positive number. - Take a for loop and iterate variable say from 1 till
`num`

. - Wherever
`num%i==0`

, print`i`

. - The
`i`

values are the factors of num.

**Program:**

class Main { public static void main(String[] args) { // A positive number int num = 100; System.out.print("Factors of " + num + " = "); // loop iterates from 1 to num for (int i = 1; i <= num; ++i) { // if num is divisibly by i, print i if (num % i == 0) { System.out.print(i + " "); } } } }

Output: Factors of 100 = 1 2 4 5 10 20 25 50 100

### Method:-II – Java program to display factors of positive number using user-defined input

`java.util`

package provide `Scanner class`

which enables user to give inputs.

In this method we will display the factors in the similar was as that of the Method-I, but here we have only to take the number as user input.

**Approach:**

- Import Scanner class from
`java.util`

package. - Make instance of Scanner class.
- Ask user to enter the input and store it in variable say num.
- Take a for loop and iterate variable say from 1 till num.
- Wherever
`num%i==0`

, print`i`

. - The i values are the factors of num.

**Program:**

import java.util.Scanner; class Main { public static void main(String[] args) { // A positive number int num; Scanner sc= new Scanner(System.in); System.out.println("Enter a number : "); num=sc.nextInt(); System.out.print("Factors of " + num + " = "); // loop iterates from 1 to num for (int i = 1; i <= num; ++i) { // if num is divisibly by i, print i if (num % i == 0) { System.out.print(i + " "); } } } }

Output: Enter a number : 100 Factors of 100 = 1 2 4 5 10 20 25 50 100

### Method:-III – Java program to display factors of negative number using for loop

`Math.abs`

in java returns the absolute value (positive value) of a number.

Since negative numbers have not only negative factors but also positive factors. So by the help of for loop we will iterate from negative of that number till the positive value of the number. If iterative value=0, we will skip the iteration otherwise wherever iterative value is perfectly divisible, we will display them.

**Approach:**

- Declare a negative number and store in an integer variable
`num`

. - Iterate loop from
`-num`

to`+num`

(as factors of a negative number is also positive number). - If
`i`

becomes, skip the iteration - Else, if
`num%i==0`

print`i`

. `i`

is the factors of number.

**Program:**

class Main { public static void main(String[] args) { // A negative number int num = -50; System.out.print("Factors of " + num + " = "); // Loop will iterate from -50 to -50 for(int i = num; i <= Math.abs(num); ++i) { // if i=0 skip the iteration if(i == 0) { continue; } else { if (num % i == 0) { System.out.print(i + " "); } } } } }

Output: Factors of -50 = -50 -25 -10 -5 -2 -1 1 2 5 10 25 50

### Method:-IV – Java program to display factors of number using while loop

We can display the factors of a number using do while loop. The while body will iterate from 1 till the number. It prints the numbers wherever the number is divisible by iterative value. These displayed numbers are the factors of the number.

**Approach:**

- Declare
`num`

and`i`

. - Initialize
`num`

to 100 and`i`

to 1. - Take a variable say
`i`

. - With the help of while loop iterate
`i`

till`num`

- In while loop if
`i%2==0`

, print`i`

. - Increment
`i`

.

**Program:**

class Main { public static void main(String[] args) { // A positive number int num=100, i=1; System.out.print("Factors of " + num + " = "); // iterate i from 1 to num while(i <= num) { // if num is divisible by i print i if(num % i == 0) { System.out.print(i + " "); } i++; } } }

**Output**

Factors of 100 = 1 2 4 5 10 20 25 50 100

### Method:-V – Java program to display factors of number do-while loop

We can display the factors of a number using do while loop. In the do body we will if number is perfectly then we will print the numbers. Outside the do body in the while loop condition will ensure that iteration will occur only till the number.

**Approach:**

- Declare
`num`

and`i`

. - Initialize
`num`

to 100 and`i`

to 1. - In DO body execute the following.
- If
`num%i==0`

, print`i`

. - Increment
`i`

- Come out of do body.
- Taking a while loop check if
`i<num`

**Program:**

class Main { public static void main(String[] args) { // A positive number int num=100, i=1; System.out.print("Factors of " + num + " = "); // check if num perfectly divisible by i // if yes print i // after do body execution, check in while condition if i<=num do { if(num % i == 0) System.out.print(i+" "); i++; } while (i <= num); } }

Output: Factors of 100 = 1 2 4 5 10 20 25 50 100

### Method:-VI – Java program to display factors of number using recursion

In this approach we will display the factors of a number using recursion. From the main method we will pass the number as arguments and a iterative variable to a method say `factRecur`

.

The recursion method will not only check and print the factors, but also will increment the iterative variable and will again call the recursion method. This process will continue till iterative variable reaches num.

**Approach**

- Create a recursive method which accepts number and
`i`

value from main method - In the method execute the following.
- Check if i
`<=number`

- Now check if the number is divisible by
`i`

, if yes print`i`

. - Then by calling recursive method pass the number and
`i+1`

as arguments. - The method will recursively call itself till
`i`

becomes equal to the number. - In main method declare and initialize
`num`

as 100. (Pass any number you want to see factors) - Take the recursive method pass the number and 1 as arguments.

**Program:**

class Main { public static void factRecur(int no, int i) { // check i less than number if(i <= no) { // check if no is divisible by i if(no%i == 0) System.out.print(i+" "); // recursive call to pass next number factRecur(no, i+1); } } public static void main(String[] args) { // declare variable int num = 100; // Print the factors of a number System.out.print("The factors = "); factRecur(num, 1); } }

Output: The factors = 1 2 4 5 10 20 25 50 100

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