Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given

Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given

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In the previous article we have discussed Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given

In this program we are going to see how to compute (x+a)(x+b) where value of x, a and b are given by using Java programming language.

Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given

The formula of (x+a)(x+b) is given below.

(x+a)(x+b)=  x2 + x(a+b) + ab

Now we will convert this into a valid Java expression.

Let x= (x+a)(x+b)

=  x2 + x(a+b) + ab

=(x*x)+x*(a+b)+(a*b)

Example:

Suppose x=4, a=2 and b=2, Then

(x+a)(x+b)= (x*x)+x*(a+b)+(a*b)
=(4*4)+4*(2+2)+(2*2)
=16

Now let’s see different ways to compute (x+a)(x+b)

Method-1: Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given By Using Static Input Value

Approach:

  • Declare and initialize three integer variables say x, a and b.
  • By using the formula compute (x+a)(x+b)
  • Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with a integer value
        int x= 4;
        System.out.println("a= " +x);
        //declare the second integer variable with a integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the third integer variable with a integer value
        int b= 2;
        System.out.println("b= "+b);
        //declare another integer variable and assigned the formulated value to it.
        int c=  (x*x)+x*(a+b)+(a*b);
        System.out.println("(x+a)(x+b) = "+c);
    }
}

Output:

a= 4
a= 4
b= 2
(x+a)(x+b) = 48

Method-2: Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given By Using User Input Value and Pow() Function

Approach:

  • Declare three integer variables say x, a and b.
  • Prompt the user to enter the values to the corresponding variables by using Scanner class.
  • Then By using the formula compute (x+a)(x+b)
  • Print the result.

Program:

import java.lang.Math;
import  java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("x= ");
        //Take the first input from the user.
        int x= sc.nextInt();
        System.out.print("a= ");
        //Take the second input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the third input from the user.
        int b= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        double  c=  (Math.pow(x,2)+x*(a+b)+(a*b));
        //Typecasting the value of c to integer value
        System.out.println("(x+a)(x+b)= "+(int)c);	
    }
}

Output:

x= 2
a= 3
b= 4
(x+a)(x+b)= 30

Method-3: Java Program to Compute (x+a)(x+b) where Value of x, a and b are Given By Using User Defined Method

Approach:

  • Declare three integer variables say x, a and b.
  • Prompt the user to enter the values to the corresponding variables by using Scanner class.
  • Then call a user defined method say computeValue() and pass x, a and b as parameter.
  • Then inside method by using the formula compute (x+a)(x+b)
  • Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("x= ");
        //Take the first input from the user.
        int x= sc.nextInt();
        System.out.print("a= ");
        //Take the second input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the third input from the user.
        int b= sc.nextInt();
        //call the function
        computeValue(x,a,b);
    }
    
    //define the method
    public static void computeValue(int x,int a, int b)
    {
        //declare another integer variable and assigned the formulated value to it.
        int c=  (x*x)+x*(a+b)+(a*b);
        System.out.println("(x+a)(x+b) = "+c);
    }
}

Output:

x= 10
a= 5
b= 6
(x+a)(x+b) = 240

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