Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given

Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given

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In the previous article we have discussed Java Program to Compute (a+b)2+(a-b)2 where Value of a and b are Given

In this program we are going to see how to compute (a+b)2-(a-b)2 where value of a and b are given by using Java programming language.

Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given

The formula of (a+b)2-(a-b)2  is given below.

(a+b)2-(a-b)2  =  4ab

Now we will convert this into a valid Java expression.

Let x= (a+b)2-(a-b)2

= 4ab

= 4*a*b

Example:

Suppose a=2 and b=2, Then

(a+b)2-(a-b)2
= 4*a*b
= 4*2*2
= 16

Now let’s see different ways to compute (a+b)2-(a-b)2

Method-1: Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given By Using Static Input Value

Approach:

  • Declare and initialize two integer variables say a and b.
  • By using the formula compute (a+b)2-(a-b)2
  • Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with an integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the second integer variable with an integer value
        int b= 2;
        System.out.println("b= "+b);
        //declare another integer variable and assigned the formulated value to it.
        int c=  4*a*b;
        System.out.println("(a+b)2-(a-b)2 = "+c);
    }
}

Output:

a= 4
b= 2
(a+b)2-(a-b)2 = 32

Method-2: Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given By Using User Input Value

Approach:

  • Declare two integer variables say a and b.
  • Prompt the user to enter the values to the corresponding variables by using Scanner class.
  • Then By using the formula compute (a+b)2-(a-b)2
  • Print the result.

Program:

import java.lang.Math;
import  java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        int c= 4*a*b;
        //Typecasting the value of c to integer value
        System.out.println("(a+b)-(a-b)2= "+c);	
    }
}

Output:

a= 12
b= 23
(a+b)-(a-b)2= 1104

Method-3: Java Program to Compute (a+b)2-(a-b)2 where Value of a and b are Given By Using User Defined Method

Approach:

  • Declare two integer variables say a and b.
  • Prompt the user to enter the values to the corresponding variables by using Scanner class.
  • Then call a user defined method say computeValue() and pass a and b as parameter.
  • Then inside method by using the formula compute (a+b)2-(a-b)2
  • Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        //call the function
        computeValue(a,b);
    }
    
    //computeValue() method to find the value of expression
    public static void computeValue(int a, int b)
    {
        //declare another integer variable and assigned the formulated value to it.
        int c=  4*a*b;
        System.out.println("(a+b)2-(a-b)2 = "+c);
    }
}

Output:

a= 10
b= 20
(a+b)2-(a-b)2 = 800

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