Java Program to Compute (-a+b-c)2 where Value of a, b, and c are Given

In the previous article we have discussed Java Program to Compute (-a-b+c)2 where Value of a, b and c are Given

In this program we are going to see how to compute (-a+b-c)2 where value of a, b and c are given by using Java programming language.

Java Program to Compute (-a+b-c)2 where Value of a, b and c are Given

The formula of (-a + b – c)2 is given below.

(-a + b – c)2 = a2 + b2 + c2 – 2ab – 2bc + 2ca

Now we will convert this into a valid Java expression.

Let x= (- a + b – c)2

=  a2 + b+ c2 – 2ab – 2bc + 2ca

= (a * a) + (b * b) +(c*c)- (2 * a * b)-(2 * b * c)+(2 * c * a)

Example:

Suppose a=2, b=2 and c=2, then

(-a+b-c)2
= (a * a) + (b * b) +(c*c)- (2 * a * b)-(2 * b * c)+(2 * c * a)
= (2 * 2) + (2 * 2) + (2 * 2) - (2 * 2 * 2) - (2 * 2 * 2) + (2 * 2 * 2)
= 4

Now let’s see different ways to compute (-a+b-c)2

Method-1: Java Program to Compute (-a+b-c)2 where Value of a, b and c are Given By Using Static Input Value

Approach:

  • Declare and initialize three integer variables say a, b and c.
  • By using the formula compute (-a+b-c)2
  • Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with an integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the second integer variable with an integer value
        int b= 4;
        System.out.println("b= "+b);
        //declare the third integer variable with an integer value
        int c= 2;
        System.out.println("c= "+c);
        //declare another integer variable and assigned the formulated value to it.
        int d=(a * a) + (b * b) +(c*c)- (2 * a * b)+(2 * b * c)-(2 * c * a);
        System.out.println("(-a+b-c)2= "+d);
    }
}
Output:

a= 4
b= 4
c= 2
(-a+b-c)2= 4

Method-2: Java Program to Compute (-a+b-c)2 where Value of a, b and c are Given By Using Pow() Function

Approach:

  • Declare three integer variables say a, b and c.
  • Take the value of a a, b and c as user input by using Scanner class.
  • Then By using the formula compute (-a+b-c)2
  • Print the result.

Program:

import java.lang.Math;
import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        double  d=(Math.pow(a,2)) + (Math.pow(b,2)) +( Math.pow(c,2))- (2 * a * b)-(2 * b * c)+(2 * c * a);
        System.out.println("(-a+b-c)2= "+(int)d);
    }
}
Output:

a= 4
b= 5
c= 6
(-a+b-c)2= 25

Method-3: Java Program to Compute (-a+b-c)2 where Value of a, b and c are Given By Using User Defined Method

Approach:

  • Declare two integer variables say a, b and c.
  • Take the value of a and b as user input by using Scanner class.
  • Then call a user defined method say computeValue() and pass a, b and c as parameter.
  • Then inside method by using the formula compute (-a+b-c)2
  • Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //call the funtion
        computeValue(a,b,c);
    }
    //define the method
    public static void computeValue(int a, int b,int c)
    {
        //declare another integer variable and assigned the formulated value to it.
        int d=(a * a) + (b * b) +(c*c)-(2 * a * b)-(2 * b * c)+(2 * c * a);
        System.out.println("(-a+b-c)2= "+d);
    }
}
Output:

a= 8
b= 10
c= 12
(-a+b-c)2= 100

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