In the previous article we have discussed Java Program to Compute (a+b+c)2 where Value of a, b and c are Given
In this program we are going to see how to compute (a+b-c)2 where value of a, b and c are given by using Java programming language.
Java Program to Compute (a+b-c)2 where Value of a, b and c are Given
The formula of (a + b – c)2 is given below.
(a + b – c)2 = a2 + b2 + c2 + 2ab – 2bc – 2ca
Now we will convert this into a valid Java expression.
Let x = (a+b-c)2
= a2 + b2 + c2 + 2ab – 2bc – 2ca
= (a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a)
Example:
Suppose a=2, b=2, and c=2 Then (a+b+c)2 = (a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a) = (2 * 2) + (2 * 2) +(2*2)+ (2 * 2 * 2)-(2 * 2 * 2)-(2 * 2 * 2) = 4
Now let’s see different ways to compute (a+b-c)2
Method-1: Java Program to Compute (a+b-c)2 where Value of a, b and c are Given By Using Static Input Value
Approach:
- Declare and initialize three integer variables say
a
,b
andc
. - By using the formula compute (a+b-c)2
- Print the result.
Program:
class Main { public static void main(String[] args) { //declare the first integer variable with an integer value int a= 4; System.out.println("a= " +a); //declare the second integer variable with an integer value int b= 4; System.out.println("b= "+b); //declare the third integer variable with an integer value int c= 4; System.out.println("c= "+c); //declare another integer variable and assigned the formulated value to it. int d=(a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a); System.out.println("(a+b-c)2= "+d); } }
Output: a= 4 b= 4 c= 4 (a+b-c)2= 16
Method-2: Java Program to Compute (a+b-c)2 where Value of a, b, and c are Given By Using pow() function
Approach:
- Declare three integer variables say
a
,b
andc
. - Take the value of a and b as user input by using Scanner class.
- Then By using the formula compute (a+b-c)2
- Print the result.
Program:
import java.lang.Math; import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //declare another integer variable and assigned the formulated value to it. double d=(Math.pow(a,2)) + (Math.pow(b,2)) +( Math.pow(c,2))+ (2 * a * b)-(2 * b * c)-(2 * c * a); System.out.println("(a+b-c)2= "+(int)d); } }
Output: a= 4 b= 5 c= 6 (a+b-c)2= 9
Method-3: Java Program to Compute (a+b-c)2 where Value of a, b and c are Given By Using User Defined Method
Approach:
- Declare two integer variables say
a
,b
andc
. - Take the value of a and b as user input by using Scanner class.
- Then call a user defined method say
computeValue()
and pass a, b and c as parameter. - Then inside method by using the formula compute (a+b-c)2
- Print the result.
Program:
import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //call the funtion computeValue(a,b,c); } //define the method public static void computeValue(int a, int b,int c) { //declare another integer variable and assigned the formulated value to it. int d=(a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a); System.out.println("(a+b-c)2= "+d); } }
Output: a= 8 b= 10 c= 12 (a+b-c)2= 36
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