# Java Program to Compute (a+b-c)2 where Value of a, b and c are Given

In the previous article we have discussed Java Program to Compute (a+b+c)2 where Value of a, b and c are Given

In this program we are going to see how to compute (a+b-c)2 where value of a, b and c are given by using Java programming language.

## Java Program to Compute (a+b-c)2 where Value of a, b and c are Given

The formula of (a + b – c)2 is given below.

(a + b – c)2 = a2 + b2 + c2 + 2ab – 2bc – 2ca

Now we will convert this into a valid Java expression.

Let x = (a+b-c)2

=  a2 + b+ c2 + 2ab – 2bc – 2ca

= (a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a)

Example:

Suppose a=2, b=2, and c=2

Then
(a+b+c)2
= (a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a)
= (2 * 2) + (2 * 2) +(2*2)+ (2 * 2 * 2)-(2 * 2 * 2)-(2 * 2 * 2)
= 4

Now let’s see different ways to compute (a+b-c)2

### Method-1: Java Program to Compute (a+b-c)2 where Value of a, b and c are Given By Using Static Input Value

Approach:

• Declare and initialize three integer variables say a, b and c.
• By using the formula compute (a+b-c)2
• Print the result.

Program:

class Main
{
public static void main(String[] args)
{
//declare the first integer variable with an integer value
int a= 4;
System.out.println("a= " +a);
//declare the second integer variable with an integer value
int b= 4;
System.out.println("b= "+b);
//declare the third integer variable with an integer value
int c= 4;
System.out.println("c= "+c);
//declare another integer variable and assigned the formulated value to it.
int d=(a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a);
System.out.println("(a+b-c)2= "+d);
}
}

Output:

a= 4
b= 4
c= 4
(a+b-c)2= 16

### Method-2: Java Program to Compute (a+b-c)2 where Value of a, b, and c are Given By Using pow() function

Approach:

• Declare three integer variables say a, b and c.
• Take the value of a and b as user input by using Scanner class.
• Then By using the formula compute (a+b-c)2
• Print the result.

Program:

import java.lang.Math;
import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
double  d=(Math.pow(a,2)) + (Math.pow(b,2)) +( Math.pow(c,2))+ (2 * a * b)-(2 * b * c)-(2 * c * a);
System.out.println("(a+b-c)2= "+(int)d);
}
}

Output:

a= 4
b= 5
c= 6
(a+b-c)2= 9

### Method-3: Java Program to Compute (a+b-c)2 where Value of a, b and c are Given By Using User Defined Method

Approach:

• Declare two integer variables say ab and c.
• Take the value of a and b as user input by using Scanner class.
• Then call a user defined method say computeValue() and pass a, b and c as parameter.
• Then inside method by using the formula compute (a+b-c)2
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//call the funtion
computeValue(a,b,c);
}
//define the method
public static void computeValue(int a, int b,int c)
{
//declare another integer variable and assigned the formulated value to it.
int d=(a * a) + (b * b) +(c*c)+ (2 * a * b)-(2 * b * c)-(2 * c * a);
System.out.println("(a+b-c)2= "+d);
}

}

Output:

a= 8
b= 10
c= 12
(a+b-c)2= 36

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