In the previous article we have discussed Java Program to Compute (a+b+c)3 where Value of a, b and c are Given
In this program we are going to see how to compute a2+b2+c2 where value of a, b, and c are given
Java Program to Compute a2+b2+c2 where Value of a, b and c are Given
The formula of a2 + b2 + c2 is given below.
a2 + b2 + c2 = (a + b + c)2 – 2(ab + bc + ca)
Now we will convert this into a valid Java expression.
Let x= a2+b2+c2
= ((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a))
Example:
Suppose a=2, b=2 and c=2, then a2+b2+c2 = ((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a)) = ((2+2+2)*(2+2+2))-2*((2*2)+(2*2)+(2*2)) = 12
Now let’s see different ways to compute a2+b2+c2
Method-1: Java Program to Compute a2+b2+c2 where Value of a, b and c are Given By Using Static Input Value
Approach:
- Declare and initialize three integer variables say
a,bandc. - By using the formula compute a2+b2+c2
- Print the result.
Program:
class Main
{
public static void main(String[] args)
{
//declare the first integer variable with an integer value
int a= 4;
System.out.println("a= " +a);
//declare the second integer variable with an integer value
int b= 4;
System.out.println("b= "+b);
//declare the third integer variable with an integer value
int c= 2;
System.out.println("c= "+c);
//declare another integer variable and assigned the formulated value to it.
int d=((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a));
System.out.println("(a2+b2+c2)= "+d);
}
}
Output: a= 4 b= 4 c= 2 (a2+b2+c2)= 36
Method-2: Java Program to Compute a2+b2+c2 where Value of a, b, and c are Given By Using Pow() Function
Approach:
- Declare three integer variables say
a,b andc. - Take the value of a and b as user input by using Scanner class.
- Then By using the formula compute a2+b2+c2
- Print the result.
Program:
import java.lang.Math;
import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
double d=(Math.pow(a+b+c,2))-2*((a*b)+(b*c)+(c*a));
System.out.println("(a2+b2+c2)= "+(int)d);
}
}
Output: a= 4 b= 4 c= 2 (a2+b2+c2)= 36
Method-3: Java Program to Compute a2+b2+c2 where Value of a, b and c are Given By Using User Defined Method
Approach:
- Declare two integer variables say
a,bandc. - Take the value of a and b as user input by using Scanner class.
- Then call a user defined method say
computeValue()and pass a, b and c as parameter. - Then inside method by using the formula compute a2+b2+c2
- Print the result.
Program:
import java.util.Scanner;
class Main
{
public static void main(String args[])
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//call the funtion
computeValue(a,b,c);
}
//define the method
public static void computeValue(int a, int b, int c)
{
//declare another integer variable and assigned the formulated value to it.
int d=((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a));
System.out.println("(a2+b2+c2)= "+d);
}
}
Output: a= 8 b= 10 c= 12 (a2+b2+c2)= 308
Interested in programming and want to excel in it by choosing the short ways. Then, practicing with the available Java Program list is mandatory.
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