In the previous article we have discussed Java Program to Compute (a+b+c)3 where Value of a, b and c are Given
In this program we are going to see how to compute a2+b2+c2 where value of a, b, and c are given
Java Program to Compute a2+b2+c2 where Value of a, b and c are Given
The formula of a2 + b2 + c2 is given below.
a2 + b2 + c2 = (a + b + c)2 – 2(ab + bc + ca)
Now we will convert this into a valid Java expression.
Let x= a2+b2+c2
= ((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a))
Example:
Suppose a=2, b=2 and c=2, then a2+b2+c2 = ((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a)) = ((2+2+2)*(2+2+2))-2*((2*2)+(2*2)+(2*2)) = 12
Now let’s see different ways to compute a2+b2+c2
Method-1: Java Program to Compute a2+b2+c2 where Value of a, b and c are Given By Using Static Input Value
Approach:
- Declare and initialize three integer variables say
a
,b
andc
. - By using the formula compute a2+b2+c2
- Print the result.
Program:
class Main { public static void main(String[] args) { //declare the first integer variable with an integer value int a= 4; System.out.println("a= " +a); //declare the second integer variable with an integer value int b= 4; System.out.println("b= "+b); //declare the third integer variable with an integer value int c= 2; System.out.println("c= "+c); //declare another integer variable and assigned the formulated value to it. int d=((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a)); System.out.println("(a2+b2+c2)= "+d); } }
Output: a= 4 b= 4 c= 2 (a2+b2+c2)= 36
Method-2: Java Program to Compute a2+b2+c2 where Value of a, b, and c are Given By Using Pow() Function
Approach:
- Declare three integer variables say
a
,b and
c
. - Take the value of a and b as user input by using Scanner class.
- Then By using the formula compute a2+b2+c2
- Print the result.
Program:
import java.lang.Math; import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //declare another integer variable and assigned the formulated value to it. double d=(Math.pow(a+b+c,2))-2*((a*b)+(b*c)+(c*a)); System.out.println("(a2+b2+c2)= "+(int)d); } }
Output: a= 4 b= 4 c= 2 (a2+b2+c2)= 36
Method-3: Java Program to Compute a2+b2+c2 where Value of a, b and c are Given By Using User Defined Method
Approach:
- Declare two integer variables say
a
,b
andc
. - Take the value of a and b as user input by using Scanner class.
- Then call a user defined method say
computeValue()
and pass a, b and c as parameter. - Then inside method by using the formula compute a2+b2+c2
- Print the result.
Program:
import java.util.Scanner; class Main { public static void main(String args[]) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //call the funtion computeValue(a,b,c); } //define the method public static void computeValue(int a, int b, int c) { //declare another integer variable and assigned the formulated value to it. int d=((a+b+c)*(a+b+c))-2*((a*b)+(b*c)+(c*a)); System.out.println("(a2+b2+c2)= "+d); } }
Output: a= 8 b= 10 c= 12 (a2+b2+c2)= 308
Interested in programming and want to excel in it by choosing the short ways. Then, practicing with the available Java Program list is mandatory.
Related Java Programs: