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## Program to Check Whether a Number is Prime or Not

In this we will see multiple ways to check a number is Prime or not.

**Prime Number: **A prime number is that number which is only divisible by 1 and itself. If the number is divisible by any other number then it is not a prime number.

E.g.

23 is only divisible by 1 and itself, so it is prime number. 45 is divisible by 1, 3, 5, 9, 15, 45, so it is not a prime number.

And our task is to find out different approaches to check whether a number is prime or not. We will see to implement this.

Let’s see different approaches one by one.

- Check a number is Prime or not using FOR loop
- Check a number is Prime or not using WHILE loop
- Check whether a number is Prime or not using Scanner class
- Check whether a number is Prime or not using Method

### Method-I:- Check a number is Prime or not using FOR loop

We can check whether a number is prime or not by using a for loop. We will iterate for loop from 2 to number/2 as number is not divisible more than of itself. In if condition we will check whether number is divisible by any iteration, if yes the number is not prime. If no, then the number is prime number.

**Approach**

- Declare and initialize the number to be checked say no.
- Initialize a variable say temp with 0.
- Declare a variable say i which will be used in iterations.
- Take a for loop and iterate
`i`

from 2 to`no/2`

. - Inside if condition check whether
`no%i==0`

, if condition satisfies come out of the loop and print no is not a prime number. - If no not divisible by any value of
`i`

, then print no is a prime number.

**Program:**

public class PrimeorNot { public static void main(String[] args) { // declare the number to be checked int no = 68; // initially assign 0 to temp int temp = 0; // check from 2 to that number, if any found divisible by i // then the number is not a prime for (int i = 2; i <= no / 2; ++i) { // if number is divisible by any value of i, increment temp value if (no % i == 0) { temp = temp +1; // if any i value found to be divisible simply come out of the loop break; } } // if temp is 0, then the number is prime number if (temp==0) System.out.println(no + " is a prime number."); else System.out.println(no + " is not a prime number."); } }

Output: 68 is not a prime number.

### Method-II:- Check a number is Prime or not using WHILE loop

We can check whether a number is prime or not by using a for loop. Initially we will set a Boolean variable say temp and set it as false.

We will iterate for loop from 2 to number/2 as number is not divisible more than of itself. In if condition we will check whether number is divisible by any iterations, if yes set temp as true.

Now outside a for loop we will take if condition and check whether temp is true. If yes the number is prime number, else the number is not a prime number.

**Approach:**

- Declare and initialize number to be checked say
`no`

. - Declare and initialize a variable say
`i`

with 2. - Declare a Boolean variable say
`temp`

and set it false. - Take a while loop and iterate
`i`

till`no<=2`

. - In if statement check if
`no%i==0`

, if yes set temp as true and come out of the loop. - Outside while loop, check in if statement, check
`!temp`

- If value of temp is initially false, then it would be true. Print no is a prime number.
- Else, print no is not a prime number.

**Program :**

public class PrimeorNot { public static void main(String[] args) { // declare and initialize the number to be checked int no = 97, i = 2; // set temp to false boolean temp = false; // iterate from 2 to number/2 while (i <= no / 2) { // check if a number is divisible by 2 to number/2 if (no % i == 0) { // if any number divisible by i, set temp to true temp = true; // come out of the loop break; } // increment i value ++i; } // if number not divisible by any value of i, then flag is false // if !false i.e. true , then number is a prime number if (!temp) System.out.println(no + " is a prime number."); else System.out.println(no + " is not a prime number."); } }

Output: 97 is a prime number.

### Method-III: Check whether a number is Prime or not using Scanner class

`java.util`

package package provide a class Scanner. Through which by creating an instance of Scanner class we can ask user to give inputs.

This approach is almost similar to previous methods. In this approach only we have to ask user to input a number. And we can use any of the for loop or while loop as done in previous methods. Let’s see this method below.

**Approach:**

- Declare and initialize variable say
`i`

with 2. - Make instance of Scanner class.
- Declare a variable say
`no`

in which number is to be stored. - Through Scanner class ask user to enter a number and store it in
`no`

. - Declare variable say temp and set to false.
- Take a while loop and iterate
`i`

till`no<=2`

. - In if statement check if
`no%i==0`

, if yes set temp as true and come out of the loop. - Outside while loop, check in if statement check
`!temp`

- If value of temp is initially false, then it would be true. Print no is a prime number.
- Else, print no is not a prime number.

**Program:**

import java.util.Scanner; public class PrimeorNot { public static void main(String[] args) { int i=2; // create instance of scanner class Scanner sc = new Scanner(System.in); // ask user to enter a number System.out.print("Please enter a number: "); int no = sc.nextInt(); // set temp to false boolean temp = false; // iterate from 2 to number/2 while (i<= no / 2) { // check if a number is divisible by 2 to number/2 if (no % i == 0) { // if any number divisible by i, set temp to true temp = true; // come out of the loop break; } // increment i value ++i; } // if number not divisible by any value of i, then flag is false // if !false i.e. true , then number is a prime number if (!temp) System.out.println(no + " is a prime number."); else System.out.println(no + " is not a prime number."); } }

Output: Please enter a number: 26 26 is not a prime number.

### Method-IV: Check whether a number is Prime or not using Method

We can also check whether a number is prime or not through method call. In the main function we have to just pass the required number and inside the calling function it would be checked whether the number is prime or not.

**Approach:**

- Take a user defined method as
`chePrim`

which will accept integer argument say`no`

from main function. - Declare
`i,`

`temp`

and initialize temp as 0. - Check if
`no == 1 or 0`

, if yes, no is not a prime number. - If not satisfied then in else condition implement the following.
- Take a for loop and iterate
`i`

from 2 to`no/2`

. - Then inside it, in a if condition check whether
`no%i==0`

. - If yes, assign 1 to temp, and come out of the loop.
- Now take another if condition and check if
`temp=0`

. If yes, print no is a prime number otherwise print no is not a prime number.

**Program:**

public class Main { // value of number from main method is passed here as argument static void chePrim(int no) { //declare i and set temp to 0 int i,temp=0; // if no is either 0 or 1 it is not a prime number if(no==0||no==1) { System.out.println(no+" is not a prime number"); } else { // check from 2 to that number, if any found divisible by i // then the number is not a prime for(i=2;i<=no/2;i++) { // if number is divisible by any value of i, increment temp value if(no%i==0){ System.out.println(no+" is not a prime number."); temp=1; // if any i value found to be divisible simply come out of the loop break; } } // if flag is 0, then the number is prime number if(temp==0) { System.out.println(no+" is a prime number."); } else { System.out.println("The number is not a prime number"); } } } public static void main(String args[]) { // pass 53 to the calling method chePrim(53); } }

Output: 53 is a prime number.

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