Leap year java program - Java Program To Check Leap Year

Leap year java program: Guys who are serious about learning the concepts of the java programming language should practice this list of programs in java and get a good grip on it for better results in exams or interviews.

Program To Check Leap Year

Leap year program in java: In this article we will see different way to find out a year is leap year or not

Concept :

Earth takes 365.25 days to roam around the orbit of the Sun i.e., called a solar year. We always round up the days in a calendar year to 365. And we add the 4 partial days to count it to one day , then we add one day to our calendar in every four years. This year having extra one days is called a leap year.

This leap year exactly divisible by 4 , and 400 also . but in the exception the year which is a century year (i.e., ending with 00 ) is not included in the leap year .

Example – 2016 is a leap year .

2000 is a leap year .

But 1700 is not a leap year .

Now we will see one by one approach to check a year is leap year or not.

Checking a year is leap year or not by if-else ladder
Checking a year is leap year or not by using logical operator
Checking a year is leap year or not by using ternary operator

Method-1 : Checking a year is leap year or not by if-else ladder

By using if else ladder we can check a year is leap year or not .

Approach :

Enter a year .
Take a Boolean value .
Using if else ladder , check every possible condition .
At last, if Boolean value is true then year is a leap year .
If Boolean value is false, then year is not a leap year .

Let’s see the below program to understand it clearly.

Program:

import java.util.Scanner;
public class Year {

    public static void main(String[] args) 
    {
        // initializing the variable for entering the year value 
    	int y;
    	Scanner sc = new Scanner(System.in);
        // entering year, we want to check 
    	System.out.println("Enter any Year:");
    	y = sc.nextInt();
    	sc.close();
    	// initializing a boolean value .
        boolean leap = false;
        // checking year is devisable by 4 or not 
        if(y % 4 == 0)
        {
            // checking year is devisable by 100 or not 
            if( y % 100 == 0)
            {
                // checking year is devisable by 400 or not 
                if ( y % 400 == 0)
                    leap = true;
                else
                    leap = false;
            }
            else
                leap = true;
        }
        else {
            leap = false;
        }
         // printing the result .
        if(leap ==true)  
            System.out.println("\n"+ y  + " is a Leap Year.");
        else
            System.out.println("\n"+ y  + " is not a Leap Year.");
    }
}

Output:

Enter any Year:
1700
1700 is not a Leap Year.

Method-2 : Checking a year is leap year or not by using logical operator

By using logical operator, we can check a year is leap year or not.

Approach :

Enter a year .
Take a Boolean value .
In if condition we are using logical operator to check the leap year .
If condition (y%100 == 0 && y%100 != 0 || y%400 == 0) satisfies then entered year is leap year .

Program:

import java.util.Scanner;
public class Year 
{

    public static void main(String[] args) 
    {
        // initializing the variable for entering the year value 
    	int y;
     	Scanner sc = new Scanner(System.in);
        // entering year, we want to check 
    	System.out.println("Enter any Year:");
    	y = sc.nextInt();
    	sc.close();
    // checking leap year or not  using  logical operator 
        if(y%100 == 0 && y%100 != 0 ||  y%400 == 0)
            System.out.println("\n"+ y  + " is a Leap Year.");
        else
            System.out.println("\n"+ y  + " is not a Leap Year.");
    }
}

Output:

Enter any Year:
1700
1700 is not a Leap Year.

Method 3 : Checking a year is leap year or not by using ternary operator

By using ternary / comparison operator, we can check a year is leap year or not.

Approach :

Enter a year .
Take a Boolean value .
In if condition we are using logical operator to check the leap year .
Taking a variable and applying condition (y % 100 == 0) ? ( (y % 400 == 0)? true : false ) : ( y % 4 == 0 ? true : false ) will return a value true or false .
If returned value is true, then year is a leap year .

Program:

import java.util.Scanner;
public class Year 
{

    public static void main(String[] args) 
    {
        // initializing the variable for entering the year value 
    	int y ; 
    	boolean temp;
    	Scanner sc = new Scanner(System.in);
        // entering year, we want to check 
    	System.out.println("Enter any Year:");
    	y = sc.nextInt();
    	sc.close();
       // checking leap year or not  using  ternary operator 
       temp = (y % 100 == 0) ? ( (y % 400 == 0)?  true : false ) : ( y % 4 == 0  ?   true    :   false  );  
        if( temp==true) 
        {
            System.out.println("\n"+ y  + " is a Leap Year.");
        }
        else
        {
              System.out.println("\n"+ y  + " is not a Leap Year.");
        }
     }
}

Output:

Enter any Year:
1700
1700 is not a Leap Year.

Get started with learning the programming language Java from beginner to experienced level by referring to our collection of Java Programs with Source Code and become a pro in the subject.

Related Java Decision Making and Loop Programs: