# Isbn java program – Java Program to Check ISBN Number

In the previous article, we have discussed Java Program to Check Evil Number

Isbn java program: In this article we are going to understand what ISBN number is and how we can check whether a number is ISBN number or not in Java with examples.

## Program to Check ISBN Number

ISBN or Intenrational Standard Book Number is used to identify a book anywhere in the world. These numbers contain ten digits. When each digit is multiplied with its position, if the result is divisible by 11 it is said to be a genuine ISBN number.

Example :

• 1259060977:

(1*1)+(2*2)+(5*3)+(9*4)+(0*5)+(6*6)+(0*7)+(9*8)+(7*9)+(7*10)= 209

209%11=0 ISBN number

• 8147852369:

(8*1)+(1*2)+(4*3)+(7*4)+(8*5)+(5*6)+(2*7)+(3*8)+(6*9)+(9*10)= 281

281%11=6 Not an ISBN number

In the above examples the numbers 1259060977 is an ISBN numbers as the resultant sum is divisible by 11. However 8147852369 is not a ISBN number as it leaves a remainder of 6 when the sum is divided by 11.

Let’s see different ways to check ISBN number.

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Approach :

1. Enter/declare a number and store it.
2. We multiply the digits with their respective positions.
3. We add the sum of all digits.
4. If the resultant sum is exactly divisible by 11, then the number is said to be an ISBN number.

### Method-1: Java Program to Check ISBN Number By Using Static Value

import java.util.Scanner;

public class ISBNNumber
{
public static void main(String args[])
{

Scanner scan = new Scanner(System.in);

//A number declared
int num = 1259060977;

int count = 0,temp = num, sum = 0, remainder;

// Loop to iterate the digits and to find the sum
while(temp>0)
{
remainder = temp%10;
temp /= 10;
sum+= remainder*++count;
}

//dividing with 11 and checking condition
if(sum%11==0)
{
System.out.println(num+" is an ISBN number");
}
else
{
System.out.println(num+" is Not an ISBN number");
}
}
}

Output:

1259060977 is an ISBN number

### Method-2: Java Program to Check ISBN Number By User Input Value

import java.util.Scanner;

public class ISBNNumber
{
public static void main(String args[])
{

Scanner scan = new Scanner(System.in);

//Taking the number as input
//from the user using scanner class
System.out.print("Enter a number : ");
int num = scan.nextInt();

int count = 0,temp = num, sum = 0, remainder;

// Loop to iterate the digits and to find the sum
while(temp>0)
{
remainder = temp%10;
temp /= 10;
sum+= remainder*++count;
}

//dividing with 11 and checking condition
if(sum%11==0)
{
System.out.println(num+" is an ISBN number");
}
else
{
System.out.println(num+" is Not an ISBN number");
}
}
}

Output:

Case-1

Enter a number : 1259060977
1259060977 is an ISBN number

Case-2

Enter a number : 1111111111
1111111111 is an ISBN number

Case-3

Enter a number : 1239059023
1239059023 is Not an ISBN number

### Method-3: Java Program to Check ISBN Number By Using User Defined Method

import java.util.Scanner;

public class ISBNNumber
{
public static void main(String args[])
{

Scanner scan = new Scanner(System.in);

//Taking the number as input
//from the user using scanner class
System.out.print("Enter a number : ");
int num = scan.nextInt();
//calling the user defined method
//to check ISBN number or not.
checkNumber(num);
}

//checkNumber() method to check ISBN number
public static void checkNumber(int num)
{

int count = 0,temp = num, sum = 0, remainder;

// Loop to iterate the digits and to find the sum
while(temp>0)
{
remainder = temp%10;
temp /= 10;
sum+= remainder*++count;
}

//dividing with 11 and checking condition
if(sum%11==0)
{
System.out.println(num+" is an ISBN number");
}
else
{
System.out.println(num+" is Not an ISBN number");
}
}
}
Output:

Case-1

Enter a number : 1259060977
1259060977 is an ISBN number

Case-2

Enter a number : 1111111111
1111111111 is an ISBN number

Case-3

Enter a number : 1239059023
1239059023 is Not an ISBN number

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