Java Program to Check if Line Passes Through the Origin

Java Program to Check if Line Passes Through the Origin

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In the previous article, we have seen Java Program to Find Line Passing Through 2 Points

In this article we will discuss about how to find line passing through origin or not using Java programming language.

Java Program to Check if Line Passes Through the Origin

Before jumping into the program directly, let’s first know how can find line passing through origin or not

Explanation:

Equation of a line passing through two points (a1, b1) and (a2, b2) is given by

b-b1 = ((b2-b1) / (a2-a1))(a-a1) + z

If line is also passing through origin, then z=0, so equation of line becomes

b-b1 = ((b2-b1) / (a2-a1))(a-a1)

Keeping a=0, b=0 in the above equation we get,

a1(b2-b1) = b1(a2-a1)

So above equation must be satisfied if any line passing through two coordinates (a1, b1) and (a2, b2) also passes through origin (0, 0).

Method-1: Java Program to Check if Line Passes Through the Origin By Using Static Value

Approach :

  • Initialize and declare 2 point .
  • Find the Boolean value of x1.a * (x2.b - x1.b) == x1.b * (x2.a - x1.a)
  • If value is true, then line is passing through origin .
  • If not, then line is not passing through origin .

Program :

class Main
{
    // Driver method
    public static void main(String args[])
    {
        //points are declared
        IntsPoint x1 = new IntsPoint(1,28);
        IntsPoint x2 = new IntsPoint(2,56);
        boolean a= x1.a * (x2.b - x1.b) == x1.b * (x2.a - x1.a);
        if(a==true)
            System.out.println("line is passing through origin ");
        else 
           System.out.println("line is  not passing through origin "); 
    }
    
     static class IntsPoint
    {
        int a,b;
        public IntsPoint(int a, int b) 
            {
                this.a = a;
                this.b = b;
            }
    }
   
}

Output:

line is passing through origin

Method-2: Java Program to Check if Line Passes Through the Origin By User Input Value

Approach :

  • Take input of values for 2 points.
  • Find the Boolean value of x1.a * (x2.b - x1.b) == x1.b * (x2.a - x1.a)
  • If value is true, then line is passing through origin .
  • If not, then line is not passing through origin .

Program :

import java.util.*;
class Main
{
     // Driver method
    public static void main(String args[])
    {
        
        //Scanner class object created
        Scanner s = new Scanner(System.in);
        int l,m ;
        //taking input of point-1 values
        System.out.println("Enter values of point 1:");
        l=s.nextInt();
        m=s.nextInt();
        //taking input of point-2 values
        IntsPoint x1 = new IntsPoint(l, m);
        System.out.println("Enter values of point 2 :");
        l=s.nextInt();
        m=s.nextInt();
        IntsPoint x2 = new IntsPoint(l, m);
        boolean a= x1.a * (x2.b - x1.b) == x1.b * (x2.a - x1.a);
        if(a==true)
            System.out.println("line is passing through origin ");
        else 
           System.out.println("line is  not passing through origin "); 
    }
    static class IntsPoint
    {
        int a,b;
        public IntsPoint(int a, int b) 
            {
                this.a = a;
                this.b = b;
            }
    }

}


Output:

Enter values of point 1:
1 28
Enter values of point 2 :
2 56
line is passing through origin

Guys who are serious about learning the concepts of the java programming language should practice this list of programs in java and get a good grip on it for better results in exams or interviews.

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