# Order check java – Java Program to Check if All the Digits of a Number are in Increasing Order

Order check java: In the previous article, we have seen Java Program to Add Zeros to Start of a Number

In this article we are going to check if all the digits of a number are in increasing order in Java.

## Java Program to Check if All the Digits of a Number are in Increasing Order

Java check if number: We have to check if the digits in the number are in increasing order or not.

For example:

If a number is 5678 then digits in this number are 5, 6, 7, 8. So, all digits are in ascending order.

Another number is 9683 then digits are 9, 6, 8 and 3. So all digits are not in ascending order.

Let’s see different ways to check if all the digits of a number are in increasing order.

### Method-1: Java Program to Check if All the Digits of a Number are in Increasing Order By Using User Input Value

Approach:

• Ask the user to enter the number and store it.
• Use a while loop to iterate through all the digits.
• If a current digit is greater than the next digit then it is not in increasing order else it is.
• Print the result.

Program:

import java.util.*;
public class Main
{
public static void main(String[] args)
{
// Class to take input
Scanner scan = new Scanner(System.in);
System.out.print("Enter a number to check - ");
// Taking input from user
int num = scan.nextInt();
int temp = num;
// Storing the first digit
int dig = temp%10;
temp=temp/10;
// Flag to store the result
boolean flag = true;

// Loop that iterates through all digits
while(temp>0)
{
// Checking if all digits are in ascending order
if(dig<=temp%10)
{
flag = false;
break;
}
dig = temp%10;
temp=temp/10;
}
// printing the result
if(flag)
System.out.println(num+" digits are in ascending order.");
else
System.out.println(num+" digits are not in ascending order");
}
}
Output:

Enter a number to check - 456
456 digits are in ascending order

### Method-2: Java Program to Check if All the Digits of a Number are in Increasing Order By Using User Defined Method

Approach:

• Ask the user to enter the number and store it.
• Then call a method to check order of digits by passing that number as parameter.
• Use a while loop to iterate through all the digits.
• If a current digit is greater than the next digit then it is not in increasing order else it is.
• Print the result.

Program:

import java.util.*;
public class Main
{
public static void main(String[] args)
{
// Class to take input
Scanner scan = new Scanner(System.in);
System.out.print("Enter a number to check - ");
// Taking input from user
int num = scan.nextInt();
//calling checkOrder() method
checkOrder(num);
}

public static void  checkOrder(int num)
{
int temp = num;
// Storing the first digit
int dig = temp%10;
temp=temp/10;
// Flag to store the result
boolean flag = true;

// Loop that iterates through all digits
while(temp>0)
{
// Checking if all digits are in ascending order
if(dig<=temp%10)
{
flag = false;
break;
}
dig = temp%10;
temp=temp/10;
}
// printing the result
if(flag)
System.out.println(num+" digits are in ascending order.");
else
System.out.println(num+" digits are not in ascending order");
}
}
Output:

Case-1
Enter a number to check - 2479
2479 digits are in ascending order.

Case-2
Enter a number to check - 82671
2479 digits are not in ascending order.

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